0,5x^2-3x+4=0

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Solution for 0,5x^2-3x+4=0 equation: 



0.5x^2-3x+4=0

a = 0.5; b = -3; c = +4;
Δ = b2-4ac
Δ = -32-4·0.5·4
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-1}{2*0.5}=\frac{2}{1}
=2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+1}{2*0.5}=\frac{4}{1}
=4
$

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